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[Zara]

Electron being the most stable massive structure at least in our vicinity, I assume that electron mass defines Kolmgorov length as G/c^2 * m electron- which is the same as its Swarzhield radius (factor 2) . Such a vortex is inside electron.

Next, I assume based on observed stability of galaxy rotation curve speed, that the speed of rotation of Kolmogorov vortex outer edge at Kolmogorov lenght, l planck > L kolmogorov and L compton is c. Which also coincides with Zitterbewegnung.

This means that speed of Kolmogorov vortex = Kolmogorov speed is c.

Kolmogorov has derived some formulas for turbulence that work almost everywhere, especially in superfluid turbulence:

Kolmogorov speed = c= ( viscosity* energy dissipation per mass unit )^1/4
Kolmogorov lenght= (viscosity^3/energy dissipation/mass)^1/4

From these 2 one can find Kolmogorov time = Kolmgorov length/kolmogorov speed= ( viscosity/energy dissipation rate) ^1/2

If we put in all numbers, with a factor of 2pi this leads to following values:

Kolmogorov length = 6,76*10-58 m
Kolmogorov speed= c
Kolmogorov time = (G/c^3) * m electron = 2,25* 10-66 sec
Kolmogorov frequency = c^3/G*melectron = 4,43*10E 65 1/s
Energy of dissipation per mass unit = c^5/(2*pi*G*m e)= 0,063 *10E84 J/kg
Viscosity of Aehter – 127* 10-50 m^2/s = h ( maybe) / m inertial Aether
And if we move little further, we find that:

energy dissipation rate/mass unit = c^4/viscosity = c^5/(2*pi*G*m e) =* 0,396/2*pi* 10^84 ( m^2/s^3) =1/2*pi * (Power planck/m e *)

so this dissipation rate of Aether equals Planck power dissipated over
electron mass, or , Power needed to maintain stable electron mass size
particle in our Universe.

we can also construct acceleration as:

a=c^3/viscosity = c/T = c^4/2*pi*G*m e = 1/2*pi * F planck/ me = 2,116*10^73
(m/s^2)
We may ask what is the relation between electron rest mass energy equivalent
E=m e c^2 and Planck power dissipated from aether into physical space to
sustain it?

From above, P planck = (c^4*m e * 2 pi )/viscosity, E= me c^2, so

E=m *c^2/P planck will give us time during which Planck power has to be dissipated
to maintain electron rest mass energy equivalent. If we do the math,

E/P planck= viscosity* me c^2/ c^4* me* 2 pi = 1/2pi viscosity/c^2 (s)

but viscosity/c^2 is exactly the definition of of a Kolmogorov time, or period of
the smallest Aether eddie.

so again ( taking care of 2*pi later) we can say that Planck power is
dissipated from Aehter to physical world to maintain stable electron mass
during every 1 rotation of the smallest Aether eddy which has radius =
Kolmogorov length of liquid Aether = me G/c^2.

viscosity /c^2 for Aether is *14,17* 10-66 sec*.

So with frequency 1/2pi * 4,43 * 10^65 1/s = 1/2pi* c^3/(G me ) Planck
power ( 3,628*10^52 W) is pumped in from Aether in the form of information via electron shape to maintain its form and gravitational mass and is
the reason for rest mass /energy equivalence me c^2 = 8,188E-14 J = 0,511
MeV.

Gravity is a Polymer Peptide which communicates Order throughout the Universal Organism.

Aether Wave is inherently hormonal, and the regulatory observation mechanism that allows the fabric of space-time to remain coherent, desires a cognitive faculty which ‘Feels’ through ‘Feedback Loops’ the information being conveyed by the physiological make-up of a self-organized system which is inter-locked through hyper-dimensional wormholes which are recursively entrained inside string membranes of infinite progressions of Delta Wave dream mental process’s which are linked to the ‘source specie’ of all creation(about 1/2 step before the Aleph/Zero Plasma Matrix of Imagination).

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This is pulled from a reply I gave to another site that was questioning these sorts of questions. It was called physorg though they steal your research then throw you off their boards while talking with the foremost renouned scientists in the world when you give China a piece of ice in their glass before giving them a drink. These are some very interesting topics to understand when understanding what exactly it is you are working with and the size of what you would need to make this a reality. There is a new nanotech firm going in town with a bunch of grants maybe someone will pick up on the science.