It boils al 213ΒΊC
I supose I would need a glove box. Another issue to be solved π
Also it can be obtained more easily:
2 BF3 + 6 NaH β B2H6 + 6 NaF
BF3 cames in methanol solution, but Diborane reacts with methanol, so methanol dilution of any compound must not be used π
Also it could be used in a safe way as a gas, you makes vacuum in your chamber, than open the valve of B2H6
Perhaps (i am no chemist) the method consist on buying B11, then use fluoridric acid to obtain BF3 and then try the reaction or any other:
4 BCl3 + 3 LiAlH4 β 2 B2H6 + 3 LiAlCl4
4 BF3 + 3 NaBH4 β 2 B2H6 + 3 NaBF4
I do not mind the procedure, I would be happy to have any source of boron hydride compound, it would be better using B11, not natural boron, because neutronicity increasing
(sorry because my non native english)
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